The mean deviation from the mean for the data | vedclass

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(D) Step $ 1 $: Calculate the mean $ \bar{x} $ of the given data. $ \bar{x} = \frac{3 + 10 + 10 + 4 + 7 + 10 + 5}{7} = \frac{49}{7} = 7 $. Step $ 2 $:

Vedclass · Accepted Answer

$ 2.57 $

Vedclass · Answer

(D) Step $ 1 $: Calculate the mean $ \bar{x} $ of the given data. $ \bar{x} = \frac{3 + 10 + 10 + 4 + 7 + 10 + 5}{7} = \frac{49}{7} = 7 $. Step $ 2 $: Calculate the absolute deviations from the mean $ |x_i - \bar{x}| $. $ |3 - 7| = 4 $ $ |10 - 7| = 3 $ $ |10 - 7| = 3 $ $ |4 - 7| = 3 $ $ |7 - 7| = 0 $ $ |10 - 7| = 3 $ $ |5 - 7| = 2 $ Step $ 3 $: Calculate the mean of these absolute deviations. $ 	ext{Mean Deviation} = \frac{4 + 3 + 3 + 3 + 0 + 3 + 2}{7} = \frac{18}{7} \approx 2.57 $.

$x_i$	$3$	$9$	$17$	$23$	$27$
$f_i$	$8$	$10$	$12$	$9$	$5$

Class Interval	$0-2$	$2-4$	$4-6$	$6-8$	$8-10$
Frequency	$1$	$2$	$3$	$2$	$1$

The mean deviation from the mean for the data $ 3, 10, 10, 4, 7, 10, 5 $ is:

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