The part of a transistor which is heavily doped to produce a large number of majority carriers is

For a given transistor,if $\alpha = I_C / I_E = 0.96$,then the current gain $\beta$ is:

In a common emitter transistor amplifier,the output voltage and input voltage have a phase difference of

For a common-emitter transistor amplifier, the current gain is $60$. If the emitter current is $6.6 \,mA$, then its base current is (in $\,mA$)

In the circuit shown in the figure,the current gain $\beta = 100$ for an $npn$ transistor. What should be the base resistor $R_B$ so that $V_{CE} = 5 \text{ V}$,given $V_{BE} = 0 \text{ V}$?

$A$ transistor cannot be used as an