sin frac{pi}{16} sin frac{3pi}{16} sin frac{5 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) ધારો કે $S = \sin \frac{\pi}{16} \sin \frac{3\pi}{16} \sin \frac{5\pi}{16} \sin \frac{7\pi}{16}$.$\sin 	heta = \cos(\frac{\pi}{2} - 	heta)$ નો ઉ

Vedclass · Accepted Answer

$\frac{\sqrt{2}}{16}$

Vedclass · Answer

(B) ધારો કે $S = \sin \frac{\pi}{16} \sin \frac{3\pi}{16} \sin \frac{5\pi}{16} \sin \frac{7\pi}{16}$.$\sin 	heta = \cos(\frac{\pi}{2} - 	heta)$ નો ઉપયોગ કરતા,$\sin \frac{7\pi}{16} = \cos \frac{\pi}{16}$ અને $\sin \frac{5\pi}{16} = \cos \frac{3\pi}{16}$ મળે.તેથી,$S = (\sin \frac{\pi}{16} \cos \frac{\pi}{16}) (\sin \frac{3\pi}{16} \cos \frac{3\pi}{16})$.$2 \sin 	heta \cos 	heta = \sin 2	heta$ સૂત્રનો ઉપયોગ કરતા,$S = (\frac{1}{2} \sin \frac{\pi}{8}) (\frac{1}{2} \sin \frac{3\pi}{8}) = \frac{1}{4} \sin \frac{\pi}{8} \cos \frac{\pi}{8}$ (કારણ કે $\sin \frac{3\pi}{8} = \cos \frac{\pi}{8}$).$S = \frac{1}{8} \sin \frac{\pi}{4} = \frac{1}{8} 	imes \frac{1}{\sqrt{2}} = \frac{1}{8\sqrt{2}} = \frac{\sqrt{2}}{16}$.

$\sin \frac{\pi}{16} \sin \frac{3\pi}{16} \sin \frac{5\pi}{16} \sin \frac{7\pi}{16}$ નું મૂલ્ય શું છે?

Similar Questions

કિંમત શોધો: $\sin ^2 18^{\circ}+\sin ^2 24^{\circ}+\sin ^2 36^{\circ}+\sin ^2 42^{\circ}+\sin ^2 78^{\circ}+\sin ^2 90^{\circ}+\sin ^2 96^{\circ}+\sin ^2 102^{\circ}+\sin ^2 138^{\circ}+\sin ^2 162^{\circ}$

જો $\cosh x = \operatorname{cosec} \theta$ હોય,તો $\coth^2 \frac{x}{2} = $

જો $0 < B < A < \frac{\pi}{4}$,$\cos^2 B - \sin^2 A = \frac{\sqrt{3}+1}{4\sqrt{2}}$ અને $2 \cos A \cos B = \frac{1+\sqrt{2}+\sqrt{3}}{2\sqrt{2}}$ હોય,તો $\cos^2 \frac{4B}{3} - \sin^2 \frac{4A}{5} =$

જો $\sin \theta + \sin 2\theta + \sin 3\theta = \sin \alpha$ અને $\cos \theta + \cos 2\theta + \cos 3\theta = \cos \alpha$ હોય,તો $\theta$ ની કિંમત શોધો.

$\frac{2\sin \theta \tan \theta (1 - \tan \theta ) + 2\sin \theta \sec^2 \theta}{(1 + \tan \theta)^2} = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module