sin^{-1}left(cos frac{53pi}{5}right) નું મૂલ્ | vedclass

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(D) આપેલ પદ: $\sin^{-1}\left(\cos \frac{53\pi}{5}\right)$ આપણે $\frac{53\pi}{5}$ ને $10\pi + \frac{3\pi}{5}$ તરીકે લખી શકીએ છીએ. તેથી,$\cos\left(10\pi

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$-\frac{\pi}{10}$

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(D) આપેલ પદ: $\sin^{-1}\left(\cos \frac{53\pi}{5}\right)$ આપણે $\frac{53\pi}{5}$ ને $10\pi + \frac{3\pi}{5}$ તરીકે લખી શકીએ છીએ. તેથી,$\cos\left(10\pi + \frac{3\pi}{5}\right) = \cos\left(\frac{3\pi}{5}\right)$. હવે,$\sin^{-1}\left(\cos \frac{3\pi}{5}\right) = \sin^{-1}\left(\sin\left(\frac{\pi}{2} - \frac{3\pi}{5}\right)\right)$ $= \sin^{-1}\left(\sin\left(\frac{5\pi - 6\pi}{10}\right)\right)$ $= \sin^{-1}\left(\sin\left(-\frac{\pi}{10}\right)\right)$ $= -\frac{\pi}{10}$.

$\sin^{-1}\left(\cos \frac{53\pi}{5}\right)$ નું મૂલ્ય શું છે?

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