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(D) Given:Voltage gain $(A_v)$ = $300$Current amplification factor $(\beta)$ = $60$Collector resistance $(R_C)$ = $5 \, k\Omega$We know that the volta

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$1 \, k\Omega$

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(D) Given:Voltage gain $(A_v)$ = $300$Current amplification factor $(\beta)$ = $60$Collector resistance $(R_C)$ = $5 \, k\Omega$We know that the voltage gain $(A_v)$ in a common emitter configuration is given by:$A_v = \beta 	imes \frac{R_C}{R_B}$Rearranging the formula to find the base resistance $(R_B)$:$R_B = \beta 	imes \frac{R_C}{A_v}$Substituting the given values:$R_B = 60 	imes \frac{5 \, k\Omega}{300}$$R_B = 60 	imes \frac{5}{300} \, k\Omega$$R_B = \frac{300}{300} \, k\Omega$$R_B = 1 \, k\Omega$Therefore, the base resistance is $1 \, k\Omega$.

The voltage gain and the current amplification factor of a transistor in common emitter configuration are $300$ and $60$ respectively. If the collector resistance is $5 \, k\Omega$, then the base resistance is:

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