mathop {lim }limits_{x to 0} frac{{sqrt {1 + | vedclass

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(B) ધારો કે $L = \mathop {\lim }\limits_{x 	o 0} \frac{{\sqrt {1 + x} - \sqrt {1 - x} }}{{\sqrt {2 + 3x} - \sqrt {2 - 3x} }}$.અંશ અને છેદનું સંમેયીકર

Vedclass · Accepted Answer

$0$ અને $\frac{1}{2}$ ની વચ્ચે છે

Vedclass · Answer

(B) ધારો કે $L = \mathop {\lim }\limits_{x 	o 0} \frac{{\sqrt {1 + x} - \sqrt {1 - x} }}{{\sqrt {2 + 3x} - \sqrt {2 - 3x} }}$.અંશ અને છેદનું સંમેયીકરણ કરતા:$L = \mathop {\lim }\limits_{x 	o 0} \frac{(\sqrt{1+x} - \sqrt{1-x})(\sqrt{1+x} + \sqrt{1-x})}{(\sqrt{2+3x} - \sqrt{2-3x})(\sqrt{2+3x} + \sqrt{2-3x})} 	imes \frac{\sqrt{2+3x} + \sqrt{2-3x}}{\sqrt{1+x} + \sqrt{1-x}}$$L = \mathop {\lim }\limits_{x 	o 0} \frac{(1+x) - (1-x)}{(2+3x) - (2-3x)} 	imes \frac{\sqrt{2+3x} + \sqrt{2-3x}}{\sqrt{1+x} + \sqrt{1-x}}$$L = \mathop {\lim }\limits_{x 	o 0} \frac{2x}{6x} 	imes \frac{\sqrt{2+3x} + \sqrt{2-3x}}{\sqrt{1+x} + \sqrt{1-x}}$$L = \frac{1}{3} 	imes \frac{\sqrt{2} + \sqrt{2}}{1 + 1} = \frac{1}{3} 	imes \frac{2\sqrt{2}}{2} = \frac{\sqrt{2}}{3}$.$\sqrt{2} \approx 1.414$ હોવાથી,$\frac{\sqrt{2}}{3} \approx 0.471$.આમ,$0 તેથી,સાચો વિકલ્પ $B$ છે.

$\mathop {\lim }\limits_{x \to 0} \frac{{\sqrt {1 + x} - \sqrt {1 - x} }}{{\sqrt {2 + 3x} - \sqrt {2 - 3x} }}$ માટે સાચું વિધાન કયું છે?

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