Two coins are tossed. What is the probability | vedclass

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(D) When two coins are tossed,the sample space $S$ is given by: $S = \{(H, H), (H, T), (T, H), (T, T)\}$ Thus,the total number of outcomes is $n(S) =

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$1$

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(D) When two coins are tossed,the sample space $S$ is given by: $S = \{(H, H), (H, T), (T, H), (T, T)\}$ Thus,the total number of outcomes is $n(S) = 4$. Let $E$ be the event of getting at most two heads. 'At most two heads' means getting $0, 1,$ or $2$ heads. All outcomes in the sample space satisfy this condition: $E = \{(H, H), (H, T), (T, H), (T, T)\}$ Thus,the number of favorable outcomes is $n(E) = 4$. The probability $P(E)$ is given by: $P(E) = \frac{n(E)}{n(S)} = \frac{4}{4} = 1$.

Two coins are tossed. What is the probability of getting at most two heads?

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