Two sides of a triangle are of lengths $5\, cm$ and $1.5\, cm$. The length of the third side of the triangle cannot be (in $cm$):

  • A
    $3.4$
  • B
    $3.8$
  • C
    $4.1$
  • D
    $3.6$

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$\angle ACD$ is an exterior angle of $\Delta ABC$. If $AB = AC$ and $\angle B = 70^{\circ}$,then $\angle ACD = \dots$ (in $^{\circ}$)

$S$ is any point in the interior of $\triangle PQR$. Show that $SQ + SR < PQ + PR$.

If $\Delta ABC \cong \Delta RPQ$ and the perimeter of $\Delta ABC$ is $18 \, cm$,then the perimeter of $\Delta PQR$ is $cm$.

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If $AB = QR$,$BC = PR$,and $CA = PQ$,then

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