Two teams A and B have the same mean and thei | vedclass

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(C) Given that the means are equal,let $\bar{X}_A = \bar{X}_B = \bar{X}$.The coefficient of variation $(CV)$ is given by $CV = \frac{\sigma}{\bar{X}}

Vedclass · Accepted Answer

$\sigma_A = 2 \sigma_B$

Vedclass · Answer

(C) Given that the means are equal,let $\bar{X}_A = \bar{X}_B = \bar{X}$.The coefficient of variation $(CV)$ is given by $CV = \frac{\sigma}{\bar{X}} 	imes 100$.For team $A$,$CV_A = \frac{\sigma_A}{\bar{X}} 	imes 100 = 4$.For team $B$,$CV_B = \frac{\sigma_B}{\bar{X}} 	imes 100 = 2$.Dividing the two equations:$\frac{CV_A}{CV_B} = \frac{\sigma_A / \bar{X}}{\sigma_B / \bar{X}} = \frac{4}{2}$.$\frac{\sigma_A}{\sigma_B} = 2$.Therefore,$\sigma_A = 2 \sigma_B$.

$x_i$	$5$	$7$	$9$	$11$
$f_i$	$3$	$2$	$1$	$2$

Two teams $A$ and $B$ have the same mean and their coefficients of variation are $4$ and $2$,respectively. If $\sigma_A$ and $\sigma_B$ are the standard deviations of teams $A$ and $B$ respectively,then the relation between them is

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