What is the area of the plates of a 3,F paral | vedclass

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(A) The capacitance of a parallel plate capacitor is given by the formula $C = \frac{\varepsilon_0 A}{d}$.Rearranging the formula to solve for the are

Vedclass · Accepted Answer

$1.694 	imes 10^9\,m^2$

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(A) The capacitance of a parallel plate capacitor is given by the formula $C = \frac{\varepsilon_0 A}{d}$.Rearranging the formula to solve for the area $A$,we get $A = \frac{Cd}{\varepsilon_0}$.Given values are $C = 3\,F$,$d = 5\,mm = 5 	imes 10^{-3}\,m$,and $\varepsilon_0 = 8.854 	imes 10^{-12}\,F/m$.Substituting these values into the formula:$A = \frac{3 	imes 5 	imes 10^{-3}}{8.854 	imes 10^{-12}}$$A = \frac{15 	imes 10^{-3}}{8.854 	imes 10^{-12}}$$A \approx 1.694 	imes 10^9\,m^2$.

What is the area of the plates of a $3\,F$ parallel plate capacitor,if the separation between the plates is $5\,mm$?

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