Which of the following ions has the smallest | vedclass

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Question

(A) To determine the smallest radius among the given ions,we analyze their electronic configurations and nuclear charges:$1$. The ions $O^{2-}$,$F^{-}

Vedclass · Accepted Answer

$Be^{2+}$

Vedclass · Answer

(A) To determine the smallest radius among the given ions,we analyze their electronic configurations and nuclear charges:$1$. The ions $O^{2-}$,$F^{-}$,$Li^{+}$,and $Be^{2+}$ are isoelectronic,all having $10$ electrons (configuration $1s^2 2s^2 2p^6$).$2$. For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number,$Z$) increases.$3$. The atomic numbers are: $O (Z=8)$,$F (Z=9)$,$Li (Z=3)$,and $Be (Z=4)$.$4$. Among these,$Be^{2+}$ has the highest nuclear charge $(Z=4)$,which exerts the strongest attraction on the electrons,resulting in the smallest ionic radius.

Which of the following ions has the smallest radius?

Similar Questions

Assertion $(A)$: The ionic radii of $Na^{+}$ and $F^{-}$ are same.
Reason $(R)$: Both $Na^{+}$ and $F^{-}$ are isoelectronic species.
The correct answer is:

Which ion has the largest radius from the following ions?

The correct order of ionic radii for the ions $P^{3-}, S^{2-}, Ca^{2+}, K^{+}, Cl^{-}$ is:

Which of the following radius order is not correct?

The radius of isoelectronic species:

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