Which of the following statements is not true | vedclass

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(D) The correct answer is $D$. $A$. $MnCl_4^{2-}$: $Mn$ is in $+2$ oxidation state $(d^5)$. $Cl^-$ is a weak field ligand,leading to $sp^3$ hybridizat

Vedclass · Accepted Answer

$[Ni(PPh_3)_2Br_2]$ has trigonal bipyramidal geometry and one unpaired electron.

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(D) The correct answer is $D$. $A$. $MnCl_4^{2-}$: $Mn$ is in $+2$ oxidation state $(d^5)$. $Cl^-$ is a weak field ligand,leading to $sp^3$ hybridization and tetrahedral geometry. It has $5$ unpaired electrons,so it is paramagnetic. This statement is true.$B$. $[Mn(CN)_6]^{2-}$: $Mn$ is in $+4$ oxidation state $(d^3)$. It forms an octahedral complex ($d^2sp^3$ or $sp^3d^2$). It has $3$ unpaired electrons,so it is paramagnetic. This statement is true.$C$. $[CuCl_4]^{2-}$: $Cu$ is in $+2$ oxidation state $(d^9)$. It is a tetrahedral complex ($sp^3$ hybridization). However,the statement claims square planar geometry,which is incorrect for $[CuCl_4]^{2-}$. Note: $[CuCl_4]^{2-}$ is actually tetrahedral. Wait,checking the options: $[Ni(PPh_3)_2Br_2]$ is a $4$-coordinate complex,which is tetrahedral,not trigonal bipyramidal. Thus,$D$ is definitely false.$D$. $[Ni(PPh_3)_2Br_2]$: $Ni$ is in $+2$ oxidation state $(d^8)$. It is a $4$-coordinate complex,which typically adopts tetrahedral geometry,not trigonal bipyramidal. Therefore,this statement is false.

Which of the following statements is not true?

Similar Questions

Which of the following complexes does not match with the hybridization state of its metal ion?
$(i) [Ni(CO)_4], sp^3$
$(ii) [Ni(CN)_4]^{2-}, sp^3$
$(iii) [CoF_6]^{3-}, d^2sp^3$
$(iv) [Fe(CN)_6]^{3-}, sp^3d^2$

Considering $H_2O$ as a weak field ligand,the number of unpaired electrons in $[Mn(H_2O)_6]^{2+}$ will be (Atomic number of $Mn = 25$).

Octahedral complexes of copper $(II)$ undergo structural distortion (Jahn-Teller). Which one of the given copper $(II)$ complexes will show the maximum structural distortion?
($en = \text{ethylenediamine}$; $H_2N-CH_2-CH_2-NH_2$)

Which from the following statements about $[Co(NH_3)_6]^{3+}$ complex is $NOT$ correct?

Which type of atomic orbitals hybridize to form a square planar complex?

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