Easy
નીચે આપેલા નિશ્ચાયકના ઘટકોના ઉપનિશ્ચાયક (Minors) અને સહઅવયવ (Cofactors) લખો: $\left|\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right|$
(N/A) આપેલ નિશ્ચાયક $A = \left|\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right|$ છે.
ઉપનિશ્ચાયક $(M_{ij})$ અને સહઅવયવ $(A_{ij})$ ની વ્યાખ્યા મુજબ,આપણે દરેક ઘટક $a_{ij}$ માટે તેની ગણતરી કરીએ છીએ:
$M_{11} = \left|\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right| = 1, A_{11} = (-1)^{1+1} M_{11} = 1$
$M_{12} = \left|\begin{array}{ll}0 & 0 \\ 0 & 1\end{array}\right| = 0, A_{12} = (-1)^{1+2} M_{12} = 0$
$M_{13} = \left|\begin{array}{ll}0 & 1 \\ 0 & 0\end{array}\right| = 0, A_{13} = (-1)^{1+3} M_{13} = 0$
$M_{21} = \left|\begin{array}{ll}0 & 0 \\ 0 & 1\end{array}\right| = 0, A_{21} = (-1)^{2+1} M_{21} = 0$
$M_{22} = \left|\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right| = 1, A_{22} = (-1)^{2+2} M_{22} = 1$
$M_{23} = \left|\begin{array}{ll}1 & 0 \\ 0 & 0\end{array}\right| = 0, A_{23} = (-1)^{2+3} M_{23} = 0$
$M_{31} = \left|\begin{array}{ll}0 & 0 \\ 1 & 0\end{array}\right| = 0, A_{31} = (-1)^{3+1} M_{31} = 0$
$M_{32} = \left|\begin{array}{ll}1 & 0 \\ 0 & 0\end{array}\right| = 0, A_{32} = (-1)^{3+2} M_{32} = 0$
$M_{33} = \left|\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right| = 1, A_{33} = (-1)^{3+3} M_{33} = 1$
ઉપનિશ્ચાયક $(M_{ij})$ અને સહઅવયવ $(A_{ij})$ ની વ્યાખ્યા મુજબ,આપણે દરેક ઘટક $a_{ij}$ માટે તેની ગણતરી કરીએ છીએ:
$M_{11} = \left|\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right| = 1, A_{11} = (-1)^{1+1} M_{11} = 1$
$M_{12} = \left|\begin{array}{ll}0 & 0 \\ 0 & 1\end{array}\right| = 0, A_{12} = (-1)^{1+2} M_{12} = 0$
$M_{13} = \left|\begin{array}{ll}0 & 1 \\ 0 & 0\end{array}\right| = 0, A_{13} = (-1)^{1+3} M_{13} = 0$
$M_{21} = \left|\begin{array}{ll}0 & 0 \\ 0 & 1\end{array}\right| = 0, A_{21} = (-1)^{2+1} M_{21} = 0$
$M_{22} = \left|\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right| = 1, A_{22} = (-1)^{2+2} M_{22} = 1$
$M_{23} = \left|\begin{array}{ll}1 & 0 \\ 0 & 0\end{array}\right| = 0, A_{23} = (-1)^{2+3} M_{23} = 0$
$M_{31} = \left|\begin{array}{ll}0 & 0 \\ 1 & 0\end{array}\right| = 0, A_{31} = (-1)^{3+1} M_{31} = 0$
$M_{32} = \left|\begin{array}{ll}1 & 0 \\ 0 & 0\end{array}\right| = 0, A_{32} = (-1)^{3+2} M_{32} = 0$
$M_{33} = \left|\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right| = 1, A_{33} = (-1)^{3+3} M_{33} = 1$
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નીચે આપેલા નિશ્ચાયકના ઘટકોના ઉપનિશ્ચાયક (Minors) અને સહઅવયવ (Cofactors) લખો: $\left|\begin{array}{rr}2 & -4 \\ 0 & 3\end{array}\right|$
Easy
View Solutionનિશ્ચાયક $\Delta = \begin{vmatrix} a_{11} & a_{12} & a_{13} \\ a_{21} & a_{22} & a_{23} \\ a_{31} & a_{32} & a_{33} \end{vmatrix}$ માં ઘટકો $a_{11}$ અને $a_{21}$ ના ઉપનિશ્ચાયક (minors) અને સહઅવયવ (cofactors) શોધો.
Easy
View Solutionજો ${A_1}, {B_1}, {C_1}, \dots$ એ નિશ્ચાયક $\Delta = \begin{vmatrix} {a_1} & {b_1} & {c_1} \\ {a_2} & {b_2} & {c_2} \\ {a_3} & {b_3} & {c_3} \end{vmatrix}$ ના ઘટકો ${a_1}, {b_1}, {c_1}, \dots$ ના સહ-અવયવો (co-factors) હોય,તો $\begin{vmatrix} {B_2} & {C_2} \\ {B_3} & {C_3} \end{vmatrix} = $
Easy
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