Write the negation of the following statement:
$\sqrt{2}$ is not a complex number.
$\sqrt{2}$ is not a complex number.
(N/A) The negation of a statement $p$ is denoted as $\sim p$.
Given the statement $p$: $\sqrt{2}$ is not a complex number.
The negation $\sim p$ is: $\sqrt{2}$ is a complex number.
Given the statement $p$: $\sqrt{2}$ is not a complex number.
The negation $\sim p$ is: $\sqrt{2}$ is a complex number.
Explore More
Similar Questions
Which of the following is not logically equivalent to the proposition: "$A$ real number is either rational or irrational"?
Easy
View SolutionIf $p$: It is raining and $q$: It is pleasant,then the symbolic form of "It is neither raining nor pleasant" is
If $p, q, r$ are simple propositions,then $(p \wedge q) \wedge (q \wedge r)$ is true,then:
Easy
View SolutionThe negation of the inverse of the statement $\sim p \lor q$ is...
DifficultMHT CET 2026
View SolutionThe statement pattern $(p \wedge q) \to (r \vee \sim s)$ is false. Then the truth values of $p, q, r$ and $s$ are respectively
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo