A metal has 9 times 10^{28} conduction electr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The resistivity $ho$ is given by $ho = \frac{m}{ne^2	au}$, where $	au$ is the relaxation time. Also, the mean free path $\lambda$ is given b

Vedclass · Accepted Answer

$62.5$

Vedclass · Answer

(D) The resistivity $ho$ is given by $ho = \frac{m}{ne^2	au}$, where $	au$ is the relaxation time. Also, the mean free path $\lambda$ is given by $\lambda = v_d 	au$, where $v_d$ is the drift speed. From the resistivity formula, $	au = \frac{m}{ne^2ho}$. Substituting this into the mean free path formula: $\lambda = v_d \left( \frac{m}{ne^2ho} ight) = \frac{m v_d}{ne^2ho}$. Given: $m = 9 	imes 10^{-31} \ kg$, $v_d = 1.6 	imes 10^6 \ m/s$, $n = 9 	imes 10^{28} \ m^{-3}$, $e = 1.6 	imes 10^{-19} \ C$, and $ho = 1 	imes 10^{-8} \ \Omega \cdot m$. $\lambda = \frac{(9 	imes 10^{-31}) 	imes (1.6 	imes 10^6)}{(9 	imes 10^{28}) 	imes (1.6 	imes 10^{-19})^2 	imes (1 	imes 10^{-8})}$. $\lambda = \frac{14.4 	imes 10^{-25}}{9 	imes 10^{28} 	imes 2.56 	imes 10^{-38} 	imes 10^{-8}} = \frac{14.4 	imes 10^{-25}}{23.04 	imes 10^{-18}} = 0.625 	imes 10^{-7} \ m = 62.5 \ nm$.

Similar Questions

$A$ constant electric current $I$ is passed through a straight conductor of length $l$. If $S$ is the specific charge of an electron,then the total momentum of the electrons is:

Which of the following is a vector quantity?

The relationship between the electric field $E$ and the current density $J$ is given by:

There is a current of $20 \, A$ in a copper wire of $10^{-6} \, m^2$ area of cross-section. If the number of free electrons per cubic meter is $10^{29}$,then the drift velocity is:

The current density in a solid cylindrical wire of radius $R$,as a function of radial distance $r$,is given by $J(r) = J_{0}(1 - \frac{r}{R})$. The total current in the radial region $r = 0$ to $r = \frac{R}{4}$ will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module