If x+y=12 and xy=27,find the value of x^{3}+y | vedclass

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(A) We use the algebraic identity: $x^{3}+y^{3} = (x+y)^{3} - 3xy(x+y)$.Given $x+y = 12$ and $xy = 27$.Substituting these values into the identity:$x^

Vedclass · Accepted Answer

$756$

Vedclass · Answer

(A) We use the algebraic identity: $x^{3}+y^{3} = (x+y)^{3} - 3xy(x+y)$.Given $x+y = 12$ and $xy = 27$.Substituting these values into the identity:$x^{3}+y^{3} = (12)^{3} - 3(27)(12)$.Factor out $12$ to simplify the calculation:$x^{3}+y^{3} = 12(12^{2} - 3 	imes 27)$.$x^{3}+y^{3} = 12(144 - 81)$.$x^{3}+y^{3} = 12(63)$.$x^{3}+y^{3} = 756$.

If $x+y=12$ and $xy=27$,find the value of $x^{3}+y^{3}$.

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