यदि tan alpha = frac{m}{m + 1} और tan beta = | vedclass

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(B) हमें दिया गया है $	an \alpha = \frac{m}{m + 1}$ और $	an \beta = \frac{1}{2m + 1}$।सूत्र $	an(\alpha + \beta) = \frac{	an \alpha + 	an \beta}{

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$\frac{\pi}{4}$

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(B) हमें दिया गया है $	an \alpha = \frac{m}{m + 1}$ और $	an \beta = \frac{1}{2m + 1}$।सूत्र $	an(\alpha + \beta) = \frac{	an \alpha + 	an \beta}{1 - 	an \alpha 	an \beta}$ का उपयोग करने पर:$	an(\alpha + \beta) = \frac{\frac{m}{m + 1} + \frac{1}{2m + 1}}{1 - \left(\frac{m}{m + 1}ight) \left(\frac{1}{2m + 1}ight)}$$= \frac{\frac{m(2m + 1) + (m + 1)}{(m + 1)(2m + 1)}}{\frac{(m + 1)(2m + 1) - m}{(m + 1)(2m + 1)}}$$= \frac{2m^2 + m + m + 1}{2m^2 + m + 2m + 1 - m}$$= \frac{2m^2 + 2m + 1}{2m^2 + 2m + 1} = 1$चूंकि $	an(\alpha + \beta) = 1$,इसलिए $\alpha + \beta = \frac{\pi}{4}$।

यदि $\tan \alpha = \frac{m}{m + 1}$ और $\tan \beta = \frac{1}{2m + 1}$ है,तो $\alpha + \beta = $

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