यदि [x] x के महत्तम पूर्णांक फलन को दर्शाता ह | vedclass

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Question

(C) माना $I = \int_{-\frac{3}{2}}^{\frac{3}{2}}[2x-3] dx$. माना $t = 2x-3$, तो $dt = 2dx$, अतः $dx = \frac{dt}{2}$.जब $x = -\frac{3}{2}$, तब $t = -6$.

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(C) माना $I = \int_{-\frac{3}{2}}^{\frac{3}{2}}[2x-3] dx$. माना $t = 2x-3$, तो $dt = 2dx$, अतः $dx = \frac{dt}{2}$.जब $x = -\frac{3}{2}$, तब $t = -6$. जब $x = \frac{3}{2}$, तब $t = 0$.$I = \frac{1}{2} \int_{-6}^{0} [t] dt = \frac{1}{2} \sum_{n=-6}^{-1} \int_{n}^{n+1} n dt = \frac{1}{2} \sum_{n=-6}^{-1} n = \frac{1}{2} (-6-5-4-3-2-1) = \frac{1}{2} (-21) = -\frac{21}{2}$.अतः, $k = -\frac{21}{2}$.अंत में, $\left|k+\frac{1}{2}\right| = \left|-\frac{21}{2} + \frac{1}{2}\right| = \left|-\frac{20}{2}\right| = |-10| = 10$.

यदि $[x]$ $x$ के महत्तम पूर्णांक फलन को दर्शाता है और $\int_{-\frac{3}{2}}^{\frac{3}{2}}[2x-3] dx = k$ है, तो $\left|k+\frac{1}{2}\right| = $

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