In the following circuit of PN junction diode | vedclass

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(A) In the given circuit,the diodes $D_1, D_2,$ and $D_3$ are connected in parallel with the battery $E$. By observing the polarity of the diodes: $D_

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$E/R$

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(A) In the given circuit,the diodes $D_1, D_2,$ and $D_3$ are connected in parallel with the battery $E$. By observing the polarity of the diodes: $D_1$ is forward biased because its $p$-terminal is connected to the positive terminal of the battery. $D_2$ is reverse biased because its $p$-terminal is connected to the negative terminal of the battery (relative to the $n$-terminal). $D_3$ is forward biased because its $p$-terminal is connected to the positive terminal of the battery. Since the diodes are ideal,the forward-biased diodes act as short circuits (zero resistance) and the reverse-biased diode acts as an open circuit (infinite resistance). The circuit simplifies to a single loop containing the battery $E$ and the resistor $R$ in series. Therefore,the current $i$ is given by $i = E/R$.

In the following circuit of $PN$ junction diodes $D_1, D_2$ and $D_3$ are ideal,then the current $i$ is:

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