The electric current flowing through a given | vedclass

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(A) The total charge $Q$ flowing through the cross-section of the conductor is equal to the area under the $I-t$ graph.From the graph,for $0 \leq t \l

Vedclass · Accepted Answer

$3.125 	imes 10^{19}$

Vedclass · Answer

(A) The total charge $Q$ flowing through the cross-section of the conductor is equal to the area under the $I-t$ graph.From the graph,for $0 \leq t \leq 10 \ s$,the current increases linearly from $100 \ mA$ to $300 \ mA$. The area is a trapezoid: $A_1 = \frac{(100 + 300) 	imes 10^{-3} \ A}{2} 	imes 10 \ s = 2 \ C$.For $10 \ s \leq t \leq 20 \ s$,the current is constant at $300 \ mA$. The area is a rectangle: $A_2 = 300 	imes 10^{-3} \ A 	imes (20 - 10) \ s = 3 \ C$.Total charge $Q = A_1 + A_2 = 2 \ C + 3 \ C = 5 \ C$.Using the quantization of charge,$Q = ne$,where $e = 1.6 	imes 10^{-19} \ C$ is the charge of an electron.$n = \frac{Q}{e} = \frac{5}{1.6 	imes 10^{-19}} = 3.125 	imes 10^{19}$.

The electric current flowing through a given conductor varies with time as shown in the graph below. The number of free electrons which flow through a given cross-section of the conductor in the time interval $0 \leq t \leq 20 \ s$ is

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