$\sin \left[\tan ^{-1}\left(\frac{1-x^2}{2 x}\right)+\cos ^{-1}\left(\frac{1-x^2}{1+x^2}\right)\right]$ का मान है

  • A
    $0$
  • B
    $1$
  • C
    $-1$
  • D
    $\frac{1}{2}$

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Similar Questions

मान ज्ञात कीजिए: $\cot ^{ - 1}\left(\frac{xy + 1}{x - y}\right) + \cot ^{ - 1}\left(\frac{yz + 1}{y - z}\right) + \cot ^{ - 1}\left(\frac{zx + 1}{z - x}\right)$

यदि $\alpha$ और $\beta$ प्रथम चतुर्थांश में ऐसे कोण हैं कि $\tan \alpha = \frac{1}{7}$ और $\sin \beta = \frac{1}{\sqrt{10}}$,तो $\alpha + 2\beta =$ ($^{\circ}$ में)

श्रेणी का योग ज्ञात कीजिए: $\tan^{-1} \left( \frac{1}{1 + 1 \times 2} \right) + \tan^{-1} \left( \frac{1}{1 + 2 \times 3} \right) + \dots + \tan^{-1} \left( \frac{1}{1 + n(n + 1)} \right) =$

${\tan ^{ - 1}}\left[ {\cos \left( {2\,{{\tan }^{ - 1}}\frac{3}{4}} \right)\, + \,\sin \,\left( {2\,{{\cot }^{ - 1}}\frac{1}{2}} \right)} \right]$ का मान क्या है?

$\tan ^{-1} 2+\tan ^{-1} 3=$

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