$\mathop {\lim }\limits_{x \to 2} \frac{{\sqrt {1 + \sqrt {2 + x} } - \sqrt 3 }}{{x - 2}}$ નું મૂલ્ય શોધો.

  • A
    $\frac{1}{8\sqrt{3}}$
  • B
    $\frac{1}{4\sqrt{3}}$
  • C
    $0$
  • D
    આમાંથી કોઈ નહીં

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Similar Questions

આપેલ લક્ષની કિંમત શોધો: $\mathop {\lim }\limits_{x \to 1} \frac{a x^{2}+b x+c}{c x^{2}+b x+a}$,જ્યાં $a+b+c \neq 0$.

જ્યારે $x \to \frac{\pi}{4}$ હોય ત્યારે વિધેય $f(x) = \frac{2\sqrt{2} - (\cos x + \sin x)^3}{1 - \sin 2x}$ ની લક્ષ કિંમત શોધો.

જો $f(x) = \frac{x(a^x - 1)}{1 - \cos x}$ અને $g(x) = \frac{x(1 - a^x)}{a^x(\sqrt{1 - x^2} - \sqrt{1 + x^2})}$ હોય,તો $\lim_{x \to 0} (f(x) - g(x)) = $

$\lim _{n \rightarrow \infty} \frac{n !}{(n+1) !-n !} = $

$\mathop {\lim }\limits_{x \to 0} \frac{{{{\left( {1 - \cos 2x} \right)}^2}}}{{2x\tan x - x\tan 2x}}$ ની કિંમત શોધો.

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