જો $\frac{1}{x(x^2 + 1)} = \frac{A}{x} + \frac{Bx + C}{x^2 + 1}$ હોય,તો $(A, B, C) = $

  • A
    $(1, -1, 0)$
  • B
    $(-1, 0, -1)$
  • C
    $(0, 1, 1)$
  • D
    આમાંથી કોઈ નહીં

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જો $\frac{1}{x(x + 1)(x + 2)...(x + n)} = \frac{A_0}{x} + \frac{A_1}{x + 1} + \frac{A_2}{x + 2} + .... + \frac{A_n}{x + n}$ હોય,તો $A_r = $

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