જો $\frac{(x - a)(x - b)}{(x - c)(x - d)} = \frac{A}{x - c} - \frac{B}{x - d} + C$ હોય,તો $C = $

  • A
    $1$
  • B
    $2$
  • C
    $3$
  • D
    $4$

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Similar Questions

$a > 0$ માટે,ધારો કે $\frac{1}{a(a+1)(a+2) \ldots(a+20)}=\sum_{k=0}^{20} \frac{A_{k}}{a+k}$. તો $100\left(\frac{A_{14}+A_{15}}{A_{13}}\right)^{2}$ ની કિંમત $....$ છે.

જો $\frac{6 x^3+7 x^2-14 x+11}{6 x^3+x^2-10 x+3}=a+\frac{b}{x+p}+\frac{c}{q x+3}+\frac{d}{3 x+p}$ હોય,તો $\frac{a+b}{p+q}=$

જો $\frac{9x-7}{(x+3)(x^2+1)} = \frac{A}{x+3} + \frac{Bx+C}{x^2+1}$, જ્યાં $A, B, C \in \mathbb{R}$, તો $A+B+C = $

$\frac{3x+1}{(x-1)^2(x+2)}$ નું આંશિક અપૂર્ણાંક વિઘટન શું છે?

જો આપણે સંમેય અપૂર્ણાંક $\frac{1}{(1-2x)^2(1-3x)}$ ને $\frac{A}{1-3x} + \frac{B}{1-2x} + \frac{C}{(1-2x)^2}$ સ્વરૂપના આંશિક અપૂર્ણાંકોમાં વિભાજિત કરીએ,તો $\min \{A, B, C\} = $ શું થાય?

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