$\int \frac{\sin (\tan ^{-1} x)}{1+x^2} d x=$ . . . . . . $+C$.

  • A
    $-\cos (\tan ^{-1} x)$
  • B
    $\sin (\tan ^{-1} x)$
  • C
    $\cos (\tan ^{-1} x)$
  • D
    $-\sin (\tan ^{-1} x)$

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